Arctan Dev C++

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Hi everyone,

In trigonometrics, arc tangent is the inverse operation of tangent. Notice that because of the sign ambiguity, the function cannot determine with certainty in which quadrant the angle falls only by its tangent value. See atan2 for an alternative that takes a fractional argument instead.

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  • The atan2 is an inbuilt function in C STL which returns tangent inverse of (y/x), where y is the proportion of the y-coordinate and x is the proportion of the x-coordinate. The numeric value lies between – and representing the angle of a (x, y) point and positive x-axis. It is the counterclockwise angle, measured in radian, between the positive X-axis, and the point (x, y).
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I am taking a C++ 100 level beginners course and we just got this assgnment that I am stuck on. Here is the assginment description:

We are going to just compute the first 15 or so digits of π using doubles.

In any case, to compute the value of π, we need a formula for it. Let’s use the standard formula,

Arctan Dev C Pdf

π = 16arctan(1/5) - 4arctan(1/239)


This is all well and good, but in order to compute π, we need to compute arctan now. We could try to use a standard function from cmath, but let’s write our own function to compute arctan. Mathematicians tell us an easy formula to use is

arctan(x) = x - x^3/3 + x^5/5 - x^7/7 + x^9/9 - ..

The only parts that might need some thinking are the alternating signs, and the fact that the exponents and denominators both increment by 2.

Here is a sample output from the program: Auto tune efx fl studio 11.

Pi = 3.14159265358

Press any key to continue

In class, the professor told us to compare it to the programs we worked on to compute sin(x) and e^x. I have been referring to those programs I have but I still can't seem to solve it. Here is what I have so far:

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Arctan Dev C Calculator

WaltP2,905

1) Why calculate the denom and power values from scratch each time? Just add 2 each time through the loop.

Arctan Is The Same As

2) How does sign*power/denom; equate to x^5/5 ? Where's your x? Where's x^5?